Y 2 3x 3 Graph

your equations are:

y = (2/3)*x + three

and:

3x - 3y = -6

in order to graph these equations, you lot demand to solve for y.

the first one is already solved for y.

the 2nd i is solved for y in the post-obit way:

3x - 3y = -half dozen
subtract 3x from both sides of the equation to get:
-3y = -3x - vi
carve up both sides of the equation past -3 to get:
y = (-3/-3)*10 - (6/-3)
simplify this to get:
y = x - (-2)
simplify farther to get:
y = x + 2

the 2 equations that you lot can now graph are:

y = (two/iii)x + iii
y = x + two

the graph of these equations is shown beneath:

the graph shows an intersection at somewhere around x = 3 and y = 5.

yous can solve these equations by substitution to see if the answer comes out somewhere near there.

use the original equations of:

y = (2/3)10 + 3
3x - 3y = -vi

since your starting time equation has already solved for y, y'all tin use that to substitute for y in the second equation to get:

3x - 3y = -6 becomes 3x - 3*((2/3)x + 3) = -6

simplify by removing parentheses to get:

3x - 3*(2/3)10 - 3*3 = -6

simpify further to go:

3x - 2x - 9 = -6

combine like terms to go:

x - ix = -6

add 9 to both sides of the equation to gert:

10 = -6 + 9

simplify further to get:

ten = iii

you now have ten = 3 and you lot tin substitute for x in either equation to solve for y.

nosotros'll use the first equation.

the starting time equation is y = (ii/3)x + 3

substitute three for x to become:

y = (2/3)*3 + 3

simplify to get:

y = ii + 3 which becomes y = 5

your solution for this prepare of simultaneous equations is:

x = 3
y = 5

this is confirmed by the graph.

Y 2 3x 3 Graph,

Source: https://www.algebra.com/algebra/homework/Graphs/Graphs.faq.question.428586.html

Posted by: keithshou1999.blogspot.com

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